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Update Contains Duplicate - Leetcode 217.py
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Contains Duplicate - Leetcode 217/Contains Duplicate - Leetcode 217.py

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# Brute Force Solution
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class Solution:
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def containsDuplicate(self, nums: List[int]) -> bool:
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n = len(nums)
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for i in range(n):
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for j in range(n):
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if i == j:
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continue
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elif nums[i] == nums[j]:
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return True
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return False
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# Time Complexity: O(n^2)
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# Space Complexity: O(1)
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# Optimal Solution
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class Solution:
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def containsDuplicate(self, nums: list[int]) -> bool:
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h = set()

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